Stepwise Solutions for NCERT Class 6 Mathematics Chapter 11 – Algebra – Exercise – 11.2

Stepwise Solutions for NCERT Class 6 Mathematics Chapter 11 – Algebra – Exercise – 11.2

1. The side of an equilateral triangle is shown by l. Express the perimeter of the equilateral triangle using l.
Solution:
2. The side of a regular hexagon is denoted by l. Express the perimeter of the hexagon using l.  (Hint : A regular hexagon has all its six sides equal in length.)
Solution:
3. A cube is a three-dimensional figure as shown in Fig. It has six faces and all of them are identical squares. The length of an edge of the cube is given by l. Find the formula for the total length of the edges of a cube.
Solution:
4. The diameter of a circle is a line which joins two points on the circle and also passes through the centre of the circle. (In the adjoining figure AB is a diameter of the circle; C is its centre.) Express the diameter of the circle (d) in terms of its radius (r).
Solution:
5. To find sum of three numbers 14, 27 and 13, we can have two ways:
(a) We may first add 14 and 27 to get 41 and then add 13 to it to get the total sum 54 or
(b) We may add 27 and 13 to get 40 and then add 14 to get the sum 54. Thus, (14 + 27) + 13 = 14 + (27 + 13)
Solution:
You can find the solutions for Class 6 Mathematics previous exercises from here

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