CBSE 7th Class Solutions, Class 7th Maths Solutions
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NCERT Solutions for Class 7 Mathematics Chapter 6 – The Triangle and its properties – Exercise 6.5

NCERT Solutions for Class 7 Mathematics Chapter 6 – The Triangle and its properties – Exercise 6.5

1. PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
2. ABC is a triangle right angled at C. If AB = 25 cm and AC = 7 cm, find BC.
3. A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall.
4. Which of the following can be the sides of a right triangle?
(i) 2.5 cm,6.5 cm, 6 cm.
(ii) 2 cm, 2 cm, 5 cm.
(iii) 1.5 cm, 2cm, 2.5 cm.
In the case of right-angled triangles, identify the right angles.

5. A tree is broken at a height of 5 m from the ground and its top touches the ground at a distance of 12 m from the base of the tree. Find the original height of the tree.
6. Angles Q and R of a ∆PQR are 25º and 65º. Write which of the following is true:
(i) PQ^2 + QR^2 = RP^2
(ii) PQ^2 + RP^2 = QR^2
(iii) RP^2 + QR^2 = PQ^2
7. Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.
8. The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.

You can find the solutions for previous exercise from here

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