In previous Post we learnt about the Equation of motion In this post we will derive the equations.
Equation from Velocity time Relation :
Here we have velocity time graph for uniform accelerated motion.We can see that the object starts with velocity u which is not equal to zero and attains final velocity of v at time t.Draw a line parallel to CO that is AD.BD = BC – CD
( represents the change in velocity in time
interval t)
From the
graph, we observe that
BC = BD + DC = BD + OA
Substituting BC = v and OA = u,
we get v = BD + u
or BD = v – u ……………… eq(1)
From the velocity-time graph
the acceleration of the object is given by
a = Change in velocity
timetaken
= BD/ CO
Substituting OC = t, we get
a = BD/ tor BD = at……. eq(2)
Using eq(1) and (2) we get
v = u + at
