NCERT full solutions here you can find full detailed solutions for all the questions with proper format. class 10 maths ncert solutions chapter 6 exercise 6.3 .
You can see the solution for complete chapter here –
-
Complete 10th Class Maths Solution
- NCERT Class 10th Chapter 6 – Exercise 6.1 Triangles
- NCERT Class 10th Chapter 6 – Exercise 6.2 Triangles
EXERCISE – 6.3
QUE:-1 State which pairs of triangles in Fig. 6.34 are similar. Write the similarity criterion used by
you for answering the question and also write the pairs of similar triangles in the symbolic form :
SOL:-
QUE:-2 In Fig. 6.35, Δ ODC ~ D OBA, ∠ BOC = 125° and∠ CDO = 70°. Find ∠ DOC,∠ DCO and ∠ OAB.
SOL:-
QUE:-3 Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at the
point O. Using a similarity criterion for two triangles, show that OA/OC = OB/OD
SOL:-
QUE:-4 In Fig. 6.36, QR/QS = QT/PR and ∠ 1 = ∠2. Show that Δ PQS ~ Δ TQR.
SOL:-
QUE:-5 S and T are points on sides PR and QR of Δ PQR such that∠ P =∠ RTS. Show that Δ RPQ ~ ΔRTS.
SOL:-
QUE:-6 In Fig. 6.37, ifΔ ABE ≅Δ ACD, show that Δ ADE ~Δ ABC.
SOL:-
QUE:-7 In Fig. 6.38, altitudes AD and CE of Δ ABC intersect each other at the point P. Show that:
(i) Δ AEP ~ Δ CDP
(ii) Δ ABD ~ Δ CBE
(iii) Δ AEP ~ Δ ADB
(iv) Δ PDC ~ Δ BEC 
SOL:-
QUE:-8 E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that
Δ ABE ~ Δ CFB.
SOL:-
QUE:-9 In Fig. 6.39, ABC and AMP are two right triangles, right angled at B and M
respectively. Prove that:
(i) Δ ABC ~ Δ AMP
(ii) CA/PA= BC/ MP
SOL:-
QUE:-10 CD and GH are respectively the bisectors of ∠ ACB and ∠ EGF such that D and H lie
on sides AB and FE of Δ ABC and Δ EFG respectively. If Δ ABC ~ Δ FEG, show that:
(i) CD/GH= AC/FG
(ii) Δ DCB ~ Δ HGE
(iii) Δ DCA ~ Δ HGF
SOL:-
QUE:-11 In Fig. 6.40, E is a point on side CB produced of an isosceles triangle ABC
with AB = AC. If AD ⊥ BC and EF ⊥ AC, prove that Δ ABD ~ Δ ECF.
SOL:-
QUE:-12 Sides AB and BC and median AD of a triangle ABC are respectively proportional
to sides PQ and QR and median PM of Δ PQR (see Fig. 6.41). Show that Δ ABC ~ ΔPQR.
SOL:-
QUE:-13 D is a point on the side BC of a triangle ABC such that ∠ ADC = ∠ BAC. Show that CA² = CB.CD.
SOL:-
You can see the solution for complete chapter here –
Tags : ncert 10th class maths, maths solution for 10th class, 10th class maths solution chapter 6, chapter 6 maths solution, 10th class solution, solution of maths for 10th class, ncert maths solution.
