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Detailed Solutions for NCERT Class 7th Mathematics Chapter 2- Fractions and Decimals Exercise 2.7 Solutions

Detailed Maths Solutions, NCERT Class 7th Mathematics Solutions, Detailed Solutions for NCERT Class 7th Mathematics Chapter 2- Fractions and Decimals Exercise 2.7 Solutions, Mathematics Solutions for Class 7th CBSE NCERT, CBSE Maths Class 7th Solutions, Class 7th Maths Solutions,  NCERT Maths solutions for class 7th, Questions and answers of NCERT class 7th Mathematics, detailed solution Notes for NCERT Class 7th Mathematics.

Please find the detailed Solutions for class 7th Maths Chapter 2- Fractions and Decimals Exercise 2.7 Solutions, you can check all the solutions from here chapter wise

NCERT Class 7th Mathematics Chapter 2- Fractions and Decimals Exercise 2.7 Solutions

1.Find:

(i) 0.4/2

Sol: First divide 4 by 2

We get 2

Now there is one digit to the right of the decimal point in 0.4. So place the decimal point in 2 such that there would be one digit to its right.

We get 0.2.

So 0.4/2 = 0.2

(ii) 0.35/5

Sol: First divide 35 by 5

We get 7

Now there are two digits to the right of the decimal point in 0.35. So place the decimal point in 7 such that there would be two digits to its right.

We get 0.07.

So 0.35/5 = 0.07

(iii) 2.48/4

Sol: First divide 248 by 4

We get 62

Now there are two digits to the right of the decimal point in 2.48. So place the decimal point in 62 such that there would be two digits to its right.

We get 0.62.

So 2.48/4 = 0.62

(iv) 65.4/6

Sol: First divide 654 by 6

We get 109

Now there is one digit to the right of the decimal point in 65.4. So place the decimal point in 109 such that there would be one digit to its right.

We get 10.9.

So 65.4/6 = 10.9

(v) 651.2/4

Sol: First divide 6512 by 4

We get 1628

Now there is one digit to the right of the decimal point in 651.2. So place the decimal point in 1628 such that there would be one digit to its right.

We get 162.8

So 651.2/4 = 162.8

(vi) 14.49/7

Sol: First divide 1449 by 7.

We get 207.

Now there are two digits to the right of the decimal point in 14.49. So place the decimal point in 207 such that there would be two digits to its right.

We get 2.07.

So 14.49/7 = 2.07.

(vii) 3.96/4

Sol: First divide 396 by 4

We get 99.

Now there are two digits to the right of the decimal point in 3.96. So place the decimal point in 99 such that there would be two digits to its right.

We get 0.99.

So 3.96/4 = 0.99

(viii) 0.80/5

Sol: First divide 80 by 5

We get 16.

Now there are two digits to the right of the decimal point in 0.80. So place the decimal point in 16 such that there would be two digits to its right.

We get 0.16.

So 0.80/5 = 0.16

2. Find:

(i) 4.8/10

Sol: First multiply and divide by 10.

We get 4.8 * 10/ 10*10 = 48/100.

Now place the decimal point in 48 such that there would be two digits to its right because there are two zeroes in 100.

We get 0.48.

So 4.8/10 = 0.48.

(ii) 52.5/10

Sol: First multiply and divide by 10.

We get 52.5* 10/ 10*10 = 525/100.

Now place the decimal point in 525 such that there would be two digits to its right because there are two zeroes in 100.

We get 5.25

So 52.5/10 = 5.25

(iii) 0.7/10

Sol: First multiply and divide by 10.

We get 0.7* 10/ 10*10 = 7/100.

Now place the decimal point in 7 such that there would be two digits to its right because there are two zeroes in 100.

We get 0.07.

So 0.7/10 = 0.07.

(iv) 33.1/10

Sol: First multiply and divide by 10.

We get 33.1* 10/ 10*10 = 331/100.

Now place the decimal point in 331 such that there would be two digits to its right because there are two zeroes in 100.

We get 3.31.

So 33.1/10 = 3.31

(v) 272.23/10

Sol: First multiply and divide by 100.

We get 272.23* 100/ 10*100 = 27223/1000.

Now place the decimal point in 27223 such that there would be three digits to its right because there are three zeroes in 1000.

We get 27.223.

So 272.23/10 = 27.223

(vi) 0.56/10

Sol: First multiply and divide by 100.

We get 0.56* 100/ 10*100 = 56/1000.

Now place the decimal point in 56 such that there would be three digits to its right because there are three zeroes in 1000.

We get 0.056

So 0.56/10 = 0.056

(vii) 3.97/10

Sol: First multiply and divide by 100.

We get 3.97* 100/ 10*100 = 397/1000.

Now place the decimal point in 397 such that there would be three digits to its right because there are three zeroes in 1000.

We get 0.397

So 3.97/10 = 0.397

3. Find:

(i) 2.7/100

Sol: First multiply and divide by 10.

We get 2.7* 100/ 10*10 = 27/1000.

Now place the decimal point in 27 such that there would be three digits to its right because there are three zeroes in 1000.

We get 0.027.

So 2.7/100 = 0.027

(ii) 0.3/100

Sol: First multiply and divide by 10.

We get 0.3* 10/ 100*10 = 3/1000.

Now place the decimal point in 3 such that there would be three digits to its right because there are three zeroes in 1000.

We get 0.003

So 0.3/100 = 0.003

(iii) 0.78/100

Sol: First multiply and divide by 100.

We get 0.78* 100/ 100*100 = 78/10000.

Now place the decimal point in 78 such that there would be four digits to its right because there are four zeroes in 10000.

We get 0.0078

So 0.78/100 = 0.0078

(iv) 432.6/100

Sol: First multiply and divide by 10.

We get 432.6* 10/ 100*10 = 4326/1000.

Now place the decimal point in 4326 such that there would be three digits to its right because there are three zeroes in 1000.

We get 4.326

So 432.6/100 = 4.326

(v) 23.6/100

Sol: First multiply and divide by 10.

We get 23.6* 10/ 100*10 = 236/1000.

Now place the decimal point in 236 such that there would be three digits to its right because there are three zeroes in 1000

We get 0.236

So 23.6/100 = 0.236

(vi) 98.53/100

Sol: First multiply and divide by 100.

We get 98.53* 100/ 100*100 = 9853/10000.

Now place the decimal point in 9853 such that there would be four digits to its right because there are four zeroes in 10000.

We get 0.9853

So 98.53/100 = 0.9853

4. Find:

(i) 7.9/1000

Sol: First multiply and divide by 10.

We get 7.9* 10/ 1000*10 = 79/10000.

Now place the decimal point in 79 such that there would be four digits to its right because there are four zeroes in 10000

We get 0.0079

So 7.9/1000 = 0.0079

(ii) 26.3/1000

Sol: First multiply and divide by 10.

We get 26.3* 10/ 1000*10 = 263/10000.

Now place the decimal point in 263 such that there would be four digits to its right because there are four zeroes in 10000

We get 0.0263

So 26.3/1000 = 0.0263

(iii) 38.53/1000

Sol: First multiply and divide by 100.

We get 38.53* 100/ 1000*100 = 3853/100000.

Now place the decimal point in 3853 such that there would be five digits to its right because there are five zeroes in 100000

We get 0.03853

So 38.53/1000 = 0.03853

(iv) 128.9/1000

Sol: First multiply and divide by 10.

We get 128.9* 10/ 1000*10 = 1289/10000.

Now place the decimal point in 1289 such that there would be four digits to its right because there are four zeroes in 10000

We get 0.1289

So 128.9/1000 = 0.1289

(v) 0.5/1000

Sol: First multiply and divide by 10.

We get 0.5* 10/ 1000*10 = 5/10000.

Now place the decimal point in 5 such that there would be four digits to its right because there are four zeroes in 10000

We get 0.0005

So 0.5/1000 = 0.0005

5. Find:

(i) 7/3.5

Sol: First multiply and divide by 10.

We get 7* 10/ 3.5*10 = 70/35

70/35 = 2 

So  7/3.5 = 2

(ii) 36/0.2

Sol: First multiply and divide by 10.

We get 36* 10/ 0.2*10 = 360/2

360/2 = 180

So 36/0.2 = 180

(iii) 3.25/0.5

Sol: First multiply and divide by 100.

We get 3.25* 100/ 0.5*100 = 325/50

325/50 = 6.5

So  3.25/0.5 = 6.5

(iv) 30.94/0.7

Sol: First multiply and divide by 100.

We get 30.94* 100/ 0.7*100 = 3094/70

3094/70 = 44.2

So 30.94/0.7 = 44.2

(v) 0.5/0.25

Sol: First multiply and divide by 100.

We get 0.5* 100/ 0.25*100 = 50/25

50/25 = 2

So 0.5/0.25 = 2

(vi) 7.75/0.25

Sol: First multiply and divide by 100.

We get 7.75* 100/ 0.25*100 = 775/25

775/25 = 31

So 7.75/0.25 = 31

(vii) 76.5/0.15

Sol: First multiply and divide by 100.

We get 76.5* 100/ 0.15*100 = 7650/15

7650/15 = 510

So 76.5/0.15 = 510

(viii) 37.8/1.4

Sol: First multiply and divide by 10

We get 37.8* 10/ 1.4*10 = 378/14

378/14 = 27

So 37.8/1.4 = 27

(ix) 2.73/1.3

Sol: First multiply and divide by 100.

We get 2.73* 100/ 1.3*100 = 273/130

273/130 = 2.1

So 2.73/1.3 = 2.1

6. A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it cover in one litre of petrol ?

Sol: Distance covered in 2.4 litres of petrol = 43.2

So distance it will cover in 1 litre of petrol = 43.2/2.4

First multiply and divide by 10.

We get 43.2* 10/ 2.4*10 = 432/24

432/24 = 18

So 43.2/2.4 = 18

Therefore it will cover 18 kilometers in 1 litre of petrol.

You can find the solutions for previous exercise from here

You can find solution for whole chapter here –

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