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Detailed NCERT Solutions for Class 7 Maths – Chapter 6 – The Triangle and its properties – Exercise 6.2

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Please find the detailed Solutions for class 7th Maths Chapter 6 – The Triangle and its properties – Exercise 6.2 Solutions, you can check all the solutions from here chapter wise

NCERT Class 7th Mathematics Chapter 6 – The Triangle and its properties – Exercise 6.2 Solutions

1. Find the value of the unknown exterior angle x in the following diagrams:

Sol: By Exterior Angle Property of a triangle – Exterior angle of a triangle is equal to the sum of its interior opposite angles.

Sum of interior opposite angles = Exterior angle

(i) x = 50° + 70°

x = 120°

(ii) x = 65° + 45°

x = 110°

(iii) x = 40° +30°

x = 70°

(iv) x = 60° + 60°

x = 120°

(v) x = 50° + 50°

x = 100°

(vi) x = 60° + 30°

x = 90°

2. Find the value of the unknown interior angle x in the following figures: 

Sol: By Exterior Angle Property of a triangle – Exterior angle of a triangle is equal to the sum of its interior opposite angles.

Sum of interior opposite angles = Exterior angle

(i) x + 50° = 115°

x = 115° – 50°

x = 65°

(ii)  x + 70° = 100°

x = 100° – 70°

x = 30°

(iii) x + 90° = 125°

x = 125° – 90°

x = 35°

(iv) x + 60° = 120°

x = 120° – 60°

x = 60°

(v) x + 30° = 80°

x = 80° – 30°

x = 50°

(vi) x + 35° = 75°

x = 75° – 35°

x = 40°

You can find the solutions for previous exercise from here

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