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NCERT Class 6th Mathematics Chapter 1 – Knowing Our Numbers Solutions Exercise 1.2 Solutions
1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.
Sol: Number of tickets sold on first day = 1,094
Number of tickets sold on second day = 1,812
Number of tickets sold on third day = 2,050
Number of tickets sold on final day =2,751
Total number of tickets sold on all the four days = 1,094 + 1,812 + 2,050 + 2,751 = 7,707
Therefore 7,707 tickets were sold on all four days.
2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?
Sol: Runs Shekhar wants to score = 10,000
Runs scored = 6,980
Runs required = 10,000 – 6,980 = 3,020
Shekhar needs 3,020 more runs to complete 10,000 runs.
3. In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?
Sol: Votes registered by the successful candidate = 5,77,500
Votes registered by his nearest rival = 3,48,700
Winning Margin = 5,77,500 – 3,48,700 = 2,28,800
Successful candidate won the election by 2,28,800 votes.
4. Kirti bookstore sold books worth Rs 2,85,891 in the first week of June and books worth Rs 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?
Sol: Sale of Books in the first week of June = Rs 2,85,891
Sale of Books in the second week of June = Rs 4,00,768
Sale for the two weeks together = 4,00,768 + 2,85,891 = Rs 6,86,659
Sale of books was greater in second week 4,00,768 > 2,85,891
Sale of Books in the second week of June – Sale of Books in the first week of June = Rs 4,00,768 – Rs 2,85,891 = Rs 1,14,877
Sale of second week was Rs 1,14,877 more than first week.
5. Find the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once.
Sol: Let us arrange the numbers in increasing order, we get
7, 6, 4, 3 ,2
Therefore greatest five digit number using these digits = 76,432
Least five digit number using these digits each once = 23,467
Difference = 76,432 – 23,467 = 52,965
6. A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?
Sol: Screws manufactured in a day = 2,825
Screws manufactured in month of January = 2,825 * 31 (January has 31 days)
Therefore screws manufactured in January = 87,575 screws
7. A merchant had Rs 78,592 with her. She placed an order for purchasing 40 radio sets at Rs 1200 each. How much money will remain with her after the purchase?
Sol: Cost of 1 radio set = Rs 1200
Cost of 40 radio sets = 1200 * 40 = 48,000
Now, total money with merchant = 78,592
Money spent on radio sets = 48,000
Money left with her = 78,592 – 48,000 = 30,592
Money left with her after the purchase = Rs 30,592
8. A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer? (Hint: Do you need to do both the multiplications?)
Sol: Wrong answer = 7236 * 65 = 470340
Correct Answer = 7236 * 56 = 405216
Difference in answer = 470340 – 405216 = 65,124
OR
Difference in answer = 7236 * (65-56)
= 7236*9 = 65,124
9. To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? (Hint: convert data in cm.)
Sol: Cloth needed to stitch one shirt = 2 m 15 cm = 2*100 + 15 = 200 + 15 = 215 cm
Total cloth = 40 m = 40 * 100 = 4,000 cm
No. of shirts which can be stitched with this cloth = 4,000 / 215 = 18 shirts and 130 cm cloth will remain
Therefore, 18 shirts can be stitched and 1 m 30 cm cloth will remain.
10. Medicine is packed in boxes, each weighing 4 kg 500g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?
Sol: Weight of one box = 4*1000 + 500 = 4500 g
Capacity of van = 800 * 1000 gm = 8,00,000 g
No. of boxes = 8,00,000 / 4500 = 177
Therefore, 177 boxes can be loaded in the van.
11. The distance between the school and the house of a student’s house is 1 km 875 m. Everyday she walks both ways. Find the total distance covered by her in six days.
Sol: Distance covered by student in one day = 2*1.875 km = 3.750 Km
Distance covered by her in six days = 3.750 * 6 = 22.500 Km
12. A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?
Sol: Capacity of curd in the vessel = 4 Lit 500 ml = 4*1000 + 500 = 4500 ml
Capacity of one glass = 25
No. of glasses can be filled = 4500 / 25 = 180
Therefore, 180 glasses can be filled with 4 lit 500 ml of curd.
