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Questions and Solutions for NCERT Class 6th Mathematics Chapter 2 Whole Numbers – Exercise 2.2
1. Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
Sol: 837 + 208 + 363
= (837 + 363) + 208
= 1200 + 208
= 1408
(b) 1962 + 453 + 1538 + 647
Sol: 1962 + 453 + 1538 + 647
= (1962 + 1538) + (453 + 647)
= 3500 + 1100
= 4600
2. Find the product by suitable rearrangement:
(a) 2 × 1768 × 50
Sol: 2 × 1768 × 50
= (2 × 50) × 1768
= 100 × 1768
= 176800
(b) 4 × 166 × 25
Sol: 4 × 166 × 25
= (4 × 25) × 166
= 100 × 166
= 16600
(c) 8 × 291 × 125
Sol: 8 × 291 × 125
= (8 × 125) ×291
= 1000 × 291
= 291000
(d) 625 × 279 × 16
Sol: 625 × 279 × 16
= (625 × 16) × 279
= 10,000 ×279
= 2790000
(e) 285 × 5 × 60
Sol: 285 × 5 × 60
= 285 × (5 × 60)
= 285 × 300
= 85500
(f) 125 × 40 × 8 × 25
Sol: 125 × 40 × 8 × 25
= (125 × 8) × (40 × 25)
= 1000 × 1000
= 1000000
3. Find the value of the following:
(a) 297 × 17 + 297 × 3
Sol: 297 × 17 + 297 × 3
= 297 × ( 17 + 3 )
= 297 × 20
= 5940
(b) 54279 × 92 + 8 × 54279
Sol: 54279 × 92 + 8 × 54279
= 54279 × ( 92 + 8 )
= 54279 × 100
= 5427900
(c) 81265 × 169 – 81265 × 69
Sol: 81265 × 169 – 81265 × 69
= 81265 × ( 169 – 69 )
= 81265 × 100
= 8126500
(d) 3845 × 5 × 782 + 769 × 25 × 218
Sol: 3845 × 5 × 782 + 769 × 25 × 218
= 3845 × 5 × 782 + (769 × 5) × 5 × 218
= 3845 × 5 × 782 + 3845 × 5 × 218
= 3845 × 5 × ( 782 + 218)
= 3845 × 5 × 1000
= 19225000
4. Find the product using suitable properties.
(a) 738 × 103
Sol: 738 × ( 100 + 3 )
= 738 × 100 + 738 × 3
= 73800 + 2214
= 76014
(b) 854 × 102
Sol: 854 × ( 100 + 2 )
= 854 × 100 + 854 × 2
= 85400 + 1708
= 87108
(c) 258 × 1008
Sol: 258 × (1000 + 8)
= 258 × 1000 + 258×8
= 258000 + 2064
= 260064
(d) 1005 × 168
Sol: (1000 + 5) × 168
= 1000 × 168 + 5 × 168
= 168000 + 840
= 168840
5. A taxi driver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs Rs 44 per litre, how much did he spend in all on petrol?
Sol: Petrol filled on Monday = 40 litres
Petrol filled on the next day = 50 litres
Total petrol filled on both the days = 40 + 50 = 90 litres
Cost of 1 litre of petrol = Rs. 44
Cost of 90 litres of petrol = 44 × 90
= 44 × (100 – 10)
= 44 × 100 – 44 × 10
= 4400 – 440
= Rs. 3960
Therefore, he spent Rs. 3960 on petrol.
6. A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs Rs 15 per litre, how much money is due to the vendor per day?
Sol: Milk supplied by the vendor in the morning = 32 litres
Milk supplied by the vendor in the evening = 68 litres
Total milk supplied by the vendor = 32 + 68 = 100 litres
Cost of 1 litre of milk = Rs. 15
Cost of 100 litres of milk = 15 × 100 = Rs. 1500
Therefore, Rs. 1500 is due to the vendor per day.
7. Match the following:
(i) 425 × 136 = 425 × (6 + 30 +100) – (c) Distributivity of multiplication over addition.
(ii) 2 × 49 × 50 = 2 × 50 × 49 – (a) Commutativity under multiplication.
(iii) 80 + 2005 + 20 = 80 + 20 + 2005 – (b) Commutativity under addition.
